Multiplication as Repeated Addition and the Array Model
The concept of multiplication grows naturally out of addition. When the same number is added repeatedly, we can replace the repetition with a single multiplication statement.
Repeated addition: 3 + 3 + 3 + 3 = 12. We added 3 four times. We write this as 4 × 3 = 12, reading it as 'four times three' or 'four groups of three.' The multiplicand (3) is the number in each group; the multiplier (4) is the number of groups; the product (12) is the total.
The array model: Arrange objects in rows and columns. A 3 × 4 array has 3 rows and 4 columns, giving 3 × 4 = 12 objects in total. Arrays make the commutative property immediately visible: if you rotate the array 90°, a 3 × 4 array becomes a 4 × 3 array, still containing 12 objects. Arrays also help children see multiplication as an area model — a 3 × 4 rectangle covers 12 unit squares.
Skip-counting: Counting by 3s — 3, 6, 9, 12 — is a bridge between addition and multiplication. Skip-counting on a number line helps children see multiplication as equal jumps. This is a crucial early strategy before formal multiplication facts are memorised.
Developmental sequence: (1) Equal groups of physical objects. (2) Skip-counting on a number line. (3) Arrays on squared paper. (4) Symbolic multiplication sentence. (5) Multiplication tables. Only after children understand what multiplication means should table memorisation begin; rote tables without conceptual grounding are fragile and quickly forgotten.
Properties of Multiplication
Multiplication over whole numbers satisfies several important properties that CTET tests both directly (which property is being used?) and indirectly (using the property to simplify a calculation).
1. Commutative property (क्रम-विनिमेयता): p × q = q × p for all whole numbers p and q. The order of factors does not affect the product. The array model makes this visible — a 3×4 array and a 4×3 array contain the same number of objects. Teaching significance: children only need to learn one half of the multiplication table (since 6×7 = 7×6).
2. Associative property (साहचर्यता): (p × q) × r = p × (q × r). When multiplying three or more numbers, the grouping does not affect the product. For example, (2 × 3) × 4 = 6 × 4 = 24, and 2 × (3 × 4) = 2 × 12 = 24. This allows flexible regrouping in mental calculation.
3. Distributive property (वितरण नियम): p × (q + r) = p × q + p × r. Multiplication distributes over addition. This is one of the most powerful properties for mental calculation. To compute 7 × 13: split 13 = 10 + 3, then 7×13 = 7×10 + 7×3 = 70 + 21 = 91. This is the basis of the standard long multiplication algorithm and of mental arithmetic strategies.
4. Identity property (गुणात्मक तत्समक): p × 1 = 1 × p = p. Multiplying any number by 1 leaves it unchanged. One is the multiplicative identity (just as zero is the additive identity).
5. Zero property: p × 0 = 0 × p = 0. Any number multiplied by zero gives zero. Children sometimes confuse this with the additive identity: p + 0 = p (adding zero does not change), but p × 0 = 0 (multiplying by zero gives zero — a very different result).
6. Closure property: The product of any two whole numbers is always a whole number. Multiplication is closed over the set of whole numbers — the result never 'escapes' the set.
Division — Concept, Types and Properties
Division is the inverse operation of multiplication. It answers the question: if a product and one factor are known, what is the other factor? 12 ÷ 4 = 3 because 3 × 4 = 12.
Two meanings of division:
Partition (equal sharing): 12 objects shared equally among 4 people — how many does each get? Here the number of groups (4) is known; we find the size of each group (3). Example: distributing 24 sweets equally among 6 children → 24 ÷ 6 = 4 sweets each.
Quotition (measurement / grouping): 12 objects, each group contains 4 — how many groups? Here the group size (4) is known; we find the number of groups (3). Example: arranging 24 students into rows of 6 → 24 ÷ 6 = 4 rows. Both contexts produce the same symbolic statement 24 ÷ 6 = 4, but they represent different real-world situations. Good teaching uses both.
Properties of division:
- Not commutative: 12 ÷ 4 ≠ 4 ÷ 12 in general. This is a critical difference from multiplication.
- Not associative: (24 ÷ 6) ÷ 2 = 4 ÷ 2 = 2, but 24 ÷ (6 ÷ 2) = 24 ÷ 3 = 8. The result changes when grouping changes.
- Division by zero is undefined: 5 ÷ 0 has no meaning — there is no number that multiplied by zero gives 5. This is a frequent point of confusion; zero in the denominator makes a fraction undefined.
- Division by 1: p ÷ 1 = p. Dividing any number by 1 leaves it unchanged.
- Division of a number by itself: p ÷ p = 1 (for p ≠ 0). Any non-zero number divided by itself is 1.
Remainder: When 13 objects are divided equally among 4, each group gets 3 with 1 left over: 13 = 4 × 3 + 1. The relationship a = bq + r (where 0 ≤ r < b) is the division algorithm.
BODMAS — Order of Operations
When an expression contains multiple operations, we need an agreed order to evaluate them. Without such an order, the same expression could give different results. BODMAS (sometimes written PEMDAS in American notation) specifies the order:
B — Brackets (evaluate expressions inside brackets first)
O — Of (of, as in 'half of 20' = 10; also written as powers/exponents)
D — Division
M — Multiplication
A — Addition
S — Subtraction
Division and Multiplication are at the same level — when both appear, work left-to-right. Similarly, Addition and Subtraction are at the same level — left-to-right.
Worked example (from CTET 2019): 17.5 × 3 − 21 ÷ 7 − 3 × 12.5
- No brackets.
- Multiplication and Division first (left to right): 17.5 × 3 = 52.5; 21 ÷ 7 = 3; 3 × 12.5 = 37.5.
- Now the expression is: 52.5 − 3 − 37.5
- Subtraction left to right: 52.5 − 3 = 49.5; 49.5 − 37.5 = 12.
- Answer: 12.
Common error: Performing operations strictly left to right without regard for precedence — e.g., computing 17.5 × 3 − 21 as (17.5 × 3 − 21) first, giving 31.5, then proceeding incorrectly. Emphasise: multiplication and division must be completed before addition and subtraction, even when the subtraction sign appears earlier in the expression.
Teaching BODMAS: Use numerical puzzles and 'calculator mystery' activities where students discover that different orders give different results. Make the convention feel necessary, not arbitrary.
Factors, Multiples, HCF and LCM
Multiplication and division generate two fundamental relationships between numbers: being a factor and being a multiple.
Factors (गुणनखंड): A number p is a factor of n if p divides n exactly (no remainder). Equivalently, n = p × q for some whole number q. The factors of 12 are: 1, 2, 3, 4, 6, 12. Every number has at least two factors (1 and itself), except 1 (which has only one factor). Numbers with exactly two factors are prime numbers.
Multiples (गुणज): A multiple of p is any number of the form p × n where n is a natural number. The multiples of 4 are: 4, 8, 12, 16, 20, 24… Every number has infinitely many multiples. Multiples are always ≥ the original number (for positive whole numbers).
Highest Common Factor — HCF (महत्तम समापवर्तक): The HCF of two or more numbers is the largest number that divides all of them exactly. HCF(12, 18) = 6. To find HCF: list all factors of each number and identify the largest common factor. HCF is used whenever we want to divide a quantity into the largest equal groups possible.
Lowest Common Multiple — LCM (लघुत्तम समापवर्त्य): The LCM of two or more numbers is the smallest number that is a multiple of all of them. LCM(4, 6) = 12. LCM is used whenever we need to find the first point at which cyclical events coincide — for example, when two bells ringing at different intervals will ring together again.
Key relationship: For any two numbers a and b: HCF(a, b) × LCM(a, b) = a × b. This allows rapid calculation of one from the other. Example: HCF(8, 12) = 4; LCM = (8×12) ÷ 4 = 96 ÷ 4 = 24. Verify: multiples of 24 include 24 itself; 24 ÷ 8 = 3 ✓; 24 ÷ 12 = 2 ✓.
Finding LCM by prime factorisation: Express each number as a product of prime factors. Take each prime factor at its highest power from either number. Multiply those together. LCM(10, 12, 24): 10 = 2×5; 12 = 2²×3; 24 = 2³×3. LCM = 2³ × 3 × 5 = 8×3×5 = 120.
Word Problems — Fractions, Ratios and LCM Applications
CTET Paper 1 frequently presents multiplication and division through word problems that require setting up equations from a verbal description. Two recurring types are fraction-of-a-whole problems and LCM coincidence problems.
Fraction problems (CTET 2019 style): 'One-sixth of trees in a garden are neem, one-half are ashoka. There are 5 neem trees. How many eucalyptus trees are there?'
Step 1: Total trees. If 1/6 of total = 5 neem, then total = 5 × 6 = 30.
Step 2: Ashoka trees = 1/2 × 30 = 15.
Step 3: Eucalyptus = 30 − 5 − 15 = 10.
The key operation here is multiplication and division of fractions: finding the whole from a part, and finding parts of the whole. Children who know only one approach ('cross-multiply') are lost; those who understand the multiplicative relationship between a fraction and its whole can solve it in three lines.
LCM pens problem (CTET 2019 style): 'Pens come in packets of 10, 12, and 24. What is the minimum number of each packet needed to buy equal numbers of each type?'
Find LCM(10, 12, 24) = 120. Then: packets of 10 needed = 120 ÷ 10 = 12; packets of 12 needed = 120 ÷ 12 = 10; packets of 24 needed = 120 ÷ 24 = 5. Minimum packets of all three = 12 + 10 + 5 = 27 packets total. The concept is that LCM gives the smallest equal total that all three pack sizes divide evenly into.
Time coincidence problems: Two events happen at intervals of p and q units of time. They first coincide again at LCM(p, q) units after their simultaneous start. This is a direct multiplication/division application frequently tested in both P1 and P2.
Remediation context (CTET 2024 style): A child computes 26 × 5 and writes 1030 (instead of 130). The error: the child correctly knows 6×5=30 and 2×5=10, but fails to regroup — the '3' tens from 6×5=30 is not carried to the tens column. The error is a regrouping (carrying) failure, not a multiplication table error. Remediation should focus on the concept of regrouping in multiplication, not re-drilling tables.
Teaching Multiplication and Division — Strategies and Approaches
NCF 2005 and NIOS 504 both emphasise that mathematical operations must be understood, not merely memorised. For multiplication and division, this means building from concrete models through pictorial representations to abstract symbols.
Stage 1 — Concrete: Use physical objects (counters, stones, beads) to form equal groups. Ask children to show '3 groups of 4' by placing 3 groups of 4 counters. Introduce arrays using grid stamps or dot paper. Share 12 objects equally among 3 children physically before writing 12 ÷ 3 = 4.
Stage 2 — Pictorial: Draw arrays and area models. Circle groups on a number line. Use fraction diagrams for fraction-of-a-whole problems. Connect skip-counting diagrams to multiplication tables.
Stage 3 — Abstract: Write multiplication facts symbolically only after stages 1 and 2 are consolidated. Introduce the distributive law as a mental calculation shortcut: 'to multiply by 13, multiply by 10 and by 3 separately, then add.' Practice BODMAS with numerical puzzles, not just drills.
Mental multiplication strategies:
• Distributive law: 7 × 18 = 7×20 − 7×2 = 140 − 14 = 126.
• Near-doubles: 6 × 7 = 6×6 + 6 = 36 + 6 = 42.
• Factors: 6 × 14 = 6 × 7 × 2 = 42 × 2 = 84.
These strategies make multiplication meaningful rather than mechanical.
Common misconceptions to address:
• 'Multiplication always makes numbers bigger' — false for multiplication by fractions (4 × ½ = 2 < 4) or by 0 or 1.
• 'Division always makes numbers smaller' — false for division by fractions (4 ÷ ½ = 8 > 4).
• 'Remainder can be any size' — the remainder must always be less than the divisor.
These are conceptual gaps, not procedural errors, and require conceptual discussion.
Connecting multiplication to division: The inverse relationship should be taught explicitly. A fact family (e.g., 3 × 4 = 12; 4 × 3 = 12; 12 ÷ 3 = 4; 12 ÷ 4 = 3) shows the four related facts from one multiplication pair. Children who understand fact families can derive division facts from multiplication knowledge.
CTET Exam Focus
Multiplication and division questions in CTET Paper 1 fall into three broad categories: direct computation (applying BODMAS or fraction arithmetic), conceptual identification (recognising which property or error type is involved), and LCM/HCF applications.
BODMAS questions: An expression with mixed operations is given; find the value. The key discipline is to identify all multiplications and divisions first, compute them, then handle additions and subtractions left-to-right. Watch for decimal multiplication: 17.5 × 3 = 52.5, not 52 or 51.5. Do not rush — carefully extract each multiplication/division term before computing.
Fraction-of-a-whole: Given a fraction of a quantity, find the whole or another part. The strategy is always: find the whole first (whole = part ÷ fraction), then find the required part (part = whole × fraction). For the garden trees problem: whole = 5 ÷ (1/6) = 30; eucalyptus = 30 − 5 − 15 = 10.
LCM/HCF problems: Remember HCF × LCM = product of two numbers. For LCM of a set, use prime factorisation. LCM(1–10) = 2³ × 3² × 5 × 7 = 2520 (frequently tested). LCM(10, 12, 24) = 120 (pen-packet type). Always verify by checking that each original number divides the LCM exactly.
Pedagogical questions: If a child makes a specific error in multiplication (like writing 1030 for 26×5), identify the conceptual gap — regrouping/carrying — not just the surface mistake. CTET asks what the error reveals and what the remediation should be. The answer is always framed as the concept behind the error, not 'more practice with the same type.'
Properties: Know which property corresponds to which statement: p×(q+r)=pq+pr is distributive; p×q=q×p is commutative; (p×q)×r=p×(q×r) is associative; p×1=p is multiplicative identity; p×0=0 is zero property. CTET sometimes presents an example and asks which law it illustrates.
Practice Questions
Q1. Evaluate : 17.5 × 3 – 21 ÷ 7 – 3 × 12.5
Explanation: Applying BODMAS: first handle all multiplications and divisions left to right: 17.5 × 3 = 52.5; 21 ÷ 7 = 3; 3 × 12.5 = 37.5. The expression becomes 52.5 − 3 − 37.5. Subtracting left to right: 52.5 − 3 = 49.5; 49.5 − 37.5 = 12.
Source: CTET Dec 2019 Paper 1, Q36
Q2. One-sixth of the trees in a garden are neem trees. Half of the trees are Ashoka trees and the remaining are eucalyptus trees. If the number of neem trees is five, how many eucalyptus trees are there in the garden?
Explanation: 1/6 of trees are neem; there are 5 neem trees, so total = 5 × 6 = 30. Ashoka = 1/2 × 30 = 15. Eucalyptus = 30 − 5 − 15 = 10.
Source: CTET Dec 2019 Paper 1, Q37
Q3. Three brands of pens A, B and C are available in packets of 10, 12 and 24 respectively. If a shopkeeper wants to buy equal number of pens of each brand, what is the minimum number of packets of each brand, he should buy?
Explanation: LCM(10, 12, 24) = 120. Packets of 10 needed: 120÷10 = 12; packets of 12 needed: 120÷12 = 10; packets of 24 needed: 120÷24 = 5. LCM ensures every type yields the same total number of pens (120).
Source: CTET Dec 2019 Paper 1, Q31
Q4. A student of class III solved 26 × 5 as 26 × 5 ──── 1030 Revisiting which of the following will best remediate this misconception?
Explanation: 26 × 5: units digit 6×5 = 30; the child writes '0' in units place but does not carry the '3' tens. So the tens digit becomes 2×5 = 10 instead of 10+3 = 13, giving 1030 instead of 130. The error is a failure to regroup (carry) in multiplication. Remediation: teach the concept of regrouping, not re-drill of tables.
Source: CTET Jan 2024 Paper 1, Q32
Q5. A number that is divisible by all the numbers from 1 to 10 (both inclusive) is
Explanation: LCM(1–10) = 2³ × 3² × 5 × 7 = 8 × 9 × 5 × 7 = 2520. Verify: 2520 ÷ 7 = 360 ✓; 2520 ÷ 8 = 315 ✓; 2520 ÷ 9 = 280 ✓. No smaller number is divisible by all of 1 through 10 simultaneously.
Source: CTET Dec 2019 Paper 1, Q34