Mathematics · CTET Notes

Number System — HCF, LCM, BODMAS and Number Sense (P2)

At the upper-primary stage (Classes 6–8) the number system expands dramatically beyond what children met in primary school. Natural numbers and whole numbers give way to integers, rational numbers, and the first encounters with irrational numbers. Along with this expansion come powerful tools — HCF and LCM for relating numbers, BODMAS for managing complex expressions, and divisibility rules that unlock mental arithmetic. NCERT's upper-primary syllabus (as per the blue-print released for CTET) makes number sense the bedrock on which algebra, data handling, and mensuration all rest. CTET Paper 2 tests these topics directly and also asks teachers to understand the pedagogical challenges children face when number systems expand — for example, why do children find negative numbers counter-intuitive, and why do rational number operations trip up so many learners? This note covers the mathematical content and its classroom implications in full.

NaturalWholeIntegerRationalHCFLCMBODMAS

The Number System Hierarchy at Upper-Primary Level

NCERT Class 6–8 builds the number system in a clear hierarchy, each set containing all previous sets plus new elements. Understanding this structure is essential for both mathematics content questions and pedagogy questions on CTET Paper 2.

Natural numbers (N): 1, 2, 3, … — the counting numbers children learn first. These are closed under addition and multiplication but not subtraction or division.

Whole numbers (W): 0, 1, 2, 3, … — natural numbers plus zero. Adding zero extends the system to include the concept of 'none'. Still closed under addition and multiplication only.

Integers (Z): …, −3, −2, −1, 0, 1, 2, 3, … — whole numbers plus negative integers. The integer system is closed under addition, subtraction, and multiplication. Division of two integers need not yield an integer (7 ÷ 2 = 3.5).

Rational numbers (Q): All numbers expressible as p/q where p and q are integers and q ≠ 0. This includes all terminating decimals (e.g., 0.75 = 3/4) and all recurring decimals (e.g., 0.333… = 1/3). Rational numbers are dense — between any two rational numbers lies another rational number.

Irrational numbers: Numbers that cannot be expressed as p/q — their decimal expansions are non-terminating and non-recurring. Examples: √2, √3, √5, π. The square root of any prime number is irrational. NCERT introduces this concept in Class 8 (and formally in Class 9 for some boards), but CTET Paper 2 tests awareness of it.

Together, rational and irrational numbers form the real number line. Every point on the number line corresponds to exactly one real number.

Key pedagogical note: research shows children have three common misconceptions about rational numbers — (i) a fraction with a larger denominator is always larger, (ii) multiplying two numbers always gives a larger result, and (iii) every decimal is a fraction with denominator 10 or 100. Addressing these requires concrete models (fraction strips, area models, number lines).

HCF and LCM — Methods and Relationships

HCF (Highest Common Factor) and LCM (Lowest Common Multiple) are two of the most tested topics in CTET Paper 2 number system questions. Both can be found by prime factorisation or by Euclid's division algorithm (for HCF).

Prime Factorisation Method:

  • HCF = product of the lowest powers of all common prime factors
  • LCM = product of the highest powers of all prime factors (common or otherwise)

Euclid's Division Algorithm for HCF: For any two positive integers a and b (a > b): write a = bq + r. Then HCF(a, b) = HCF(b, r). Continue until remainder = 0; the last non-zero remainder is the HCF. Example: HCF(56, 15): 56 = 15(3) + 11; 15 = 11(1) + 4; 11 = 4(2) + 3; 4 = 3(1) + 1; 3 = 1(3) + 0. HCF = 1.

Key relationship: For any two positive integers a and b:
HCF(a, b) × LCM(a, b) = a × b

This means if you know the HCF and product, you can find the LCM, and vice versa.

For numbers given as a ratio: If two numbers are in ratio m : n, they can be written as mk and nk where k = HCF. Then LCM = mnk.
Example: ratio 3 : 7, LCM = 630. Numbers are 3k and 7k. LCM = 3 × 7 × k = 21k = 630, so k = 30. HCF = 30. Sum of LCM and HCF = 630 + 30 = 660.

Applications of LCM: Finding the smallest number divisible by several given numbers; scheduling problems (e.g., two events that recur after x and y days next coincide after LCM(x, y) days).

Applications of HCF: Finding the largest tile that fits a floor without cutting; dividing a collection into equal groups of maximum size.

Divisibility by multiple numbers: A number is divisible by each of 3, 5, and 7 if and only if it is divisible by LCM(3, 5, 7) = 105. Natural numbers from 1 to 500 that are multiples of 105: 105, 210, 315, 420 — exactly 4 numbers.

BODMAS and Order of Operations

BODMAS stands for Brackets, Orders (powers and roots), Division, Multiplication, Addition, Subtraction. It specifies the order in which operations in a mathematical expression must be performed. Without this convention, the same expression could yield different values depending on the order of computation.

Step-by-step BODMAS:

  1. B — Brackets: Evaluate innermost brackets first: (), then {}, then [].
  2. O — Orders: Evaluate all powers and roots next (e.g., 3² = 9, √25 = 5).
  3. D and M — Division and Multiplication: These have equal precedence; evaluate left to right.
  4. A and S — Addition and Subtraction: Equal precedence; evaluate left to right.

Common trap: Division and multiplication have the same precedence — do not always multiply before dividing. Work left to right. Similarly for addition and subtraction.

Example: 52 × 3 + 4 + √441 + 7 × 3 + 5 − 32 + 8 × 12
= 52 × 3 + 4 + 21 + 7 × 3 + 5 − 32 + 8 × 12 (√441 = 21)
= 156 + 4 + 21 + 21 + 5 − 32 + 96 (each multiplication done)
= 271

Perfect squares near a number: To find the least number that must be added to n to make it a perfect square, find the nearest perfect square above n. For n = 955: 30² = 900, 31² = 961. So add 961 − 955 = 6. If x = 6, then 3x + 2 = 20.

Pedagogical note for CTET: BODMAS errors are among the most common in Classes 6–8. Research suggests children make errors because they apply rules mechanically without understanding why the convention exists. Effective teaching asks children to evaluate the same expression with different orderings and observe inconsistent answers — motivating the need for a shared convention.

Divisibility Rules and Prime Numbers

Divisibility rules allow rapid testing whether a number is divisible by a given divisor without performing full division. These are both mathematically important and pedagogically powerful because they reveal the internal structure of the number system.

Key divisibility rules:

  • By 2: Last digit is even (0, 2, 4, 6, 8).
  • By 3: Sum of digits is divisible by 3. (e.g., 123: 1+2+3=6, divisible by 3.)
  • By 4: Last two digits form a number divisible by 4.
  • By 5: Last digit is 0 or 5.
  • By 6: Divisible by both 2 and 3.
  • By 8: Last three digits form a number divisible by 8.
  • By 9: Sum of digits is divisible by 9.
  • By 10: Last digit is 0.
  • By 11: Alternating sum of digits is divisible by 11. (Sum of digits at odd positions − sum at even positions = 0 or multiple of 11.)

Divisibility by 72: Since 72 = 8 × 9 and gcd(8,9) = 1, a number is divisible by 72 iff it is divisible by both 8 and 9. For an 8-digit number like 9471x9y2 — divisibility by 8 tests the last three digits (9y2); divisibility by 9 tests digit sum.

Prime factorisation and prime numbers: A prime number has exactly two distinct factors: 1 and itself. The Fundamental Theorem of Arithmetic states that every natural number greater than 1 can be expressed uniquely as a product of primes. This theorem underlies both HCF/LCM calculations and the structure of rational number arithmetic.

Sum of cubes and ratio: If three numbers are in ratio 2 : 3 : 4, write them as 2k, 3k, 4k. Sum of cubes: (2k)³ + (3k)³ + (4k)³ = 8k³ + 27k³ + 64k³ = 99k³ = 33957, so k³ = 343, k = 7. Sum = 2(7) + 3(7) + 4(7) = 63.

Rational Number Arithmetic — Fractions, Decimals and Negative Numbers

Rational number arithmetic is the engine of upper-primary mathematics. It encompasses fractions (proper, improper, mixed), decimals, and integers, and the operations of addition, subtraction, multiplication, and division across all three representations.

Comparing fractions: Convert to a common denominator, or use cross-multiplication. To compare p/q and r/s: compare ps with qr. The fraction with larger cross-product numerator is larger. To find the largest and smallest among several fractions, a common denominator approach is most reliable.

Mixed numbers to improper fractions: a(b/c) = (ac + b)/c. Operations on mixed numbers are usually easier after converting to improper fractions.

Integer operations — common misconceptions:

  • Children often believe subtracting a negative is the same as subtracting — e.g., 5 − (−3) = 2 rather than 8. Use the number line to demonstrate: subtracting a negative means moving right on the number line.
  • Multiplication of two negatives being positive is counter-intuitive. Pattern extension helps: (−2)(3) = −6, (−2)(2) = −4, (−2)(1) = −2, (−2)(0) = 0, (−2)(−1) = 2 — the pattern continues.

Standard form (scientific notation): A number in standard form is written as a × 10ⁿ where 1 ≤ a < 10 and n is an integer. For example: 12.34 × 10¹⁰ − 5.67 × 10⁸ = 1234 × 10⁸ − 5.67 × 10⁸ = 1228.33 × 10⁸ = 1.22833 × 10¹¹. Children often confuse moving the decimal point with changing the power of 10.

Reciprocals: The reciprocal of p/q is q/p. To divide by a fraction, multiply by its reciprocal. Finding the number by which (−1/4) must be multiplied to get the reciprocal of (−1/4)³: the reciprocal of (−1/4)³ = (−4)³ = −64, so (−1/4) × x = −64, giving x = 256.

Properties of rational numbers for CTET: Closure (Q is closed under +, −, ×, and ÷ excluding ÷0), commutativity (+, ×), associativity (+, ×), distributivity of × over +, and the existence of additive identity (0) and multiplicative identity (1), additive inverses (−p/q for p/q), and multiplicative inverses (q/p for p/q ≠ 0).

Squares, Square Roots, Cubes and Cube Roots

Perfect squares and cubes, and their roots, form a major topic at Class 7–8 level and appear regularly in CTET Paper 2 number questions.

Perfect squares: A perfect square is a number that is the square of an integer: 1, 4, 9, 16, 25, … Key properties: (i) A perfect square's prime factorisation has all even exponents. (ii) No perfect square ends in 2, 3, 7, or 8. (iii) The difference between consecutive perfect squares n² and (n+1)² is 2n+1.

Finding the nearest perfect square: To find the least number to add to n to make it a perfect square, compute ⌊√n⌋ = m. If m² = n, it is already a perfect square. Otherwise, add (m+1)² − n. To find the least number to subtract, subtract n − m².

Square root by prime factorisation: Factorise completely; pair the primes; multiply one prime from each pair. Works only for perfect squares.

Square root by long division: The algorithm for non-perfect-square roots — group digits in pairs from the decimal point, find the largest digit whose square fits, subtract, bring down, double the quotient as the new trial divisor. This gives the square root to any required number of decimal places.

Perfect cubes: A perfect cube has all prime exponents divisible by 3: 1, 8, 27, 64, 125, 216, … Property: A perfect cube can end in any digit 0–9.

Cube root by prime factorisation: Factorise; group primes in triples; take one from each triple. For example, 313632: factorising gives 2⁵ × 3² × 11⁴ — note this is written as p² × q³ × r⁴ meaning 3² × 2³ × 11⁴ (rearranging), so p=3, q=2, r=11, and p+q+r=16.

Estimating square roots: For CTET questions that involve comparing surds, finding which of √198 × √550 and √99 × √363 is larger: simplify: 198×550 = 108900 = 330², so x = 330; 99×363 = 35937 = 189.57…, so y = 189.57. Then 1/x < 1/y.

Number Sense and Its Pedagogical Development

Number sense is more than knowing how to compute — it is the ability to think flexibly about numbers, estimate efficiently, recognise relationships, and choose the most appropriate strategy for a given calculation. NCF 2005 and NIOS 504 both identify number sense as a foundational mathematical goal at upper-primary level.

Components of number sense (NCTM framework, used in NCERT):

  • Understanding numbers and number relationships — knowing that 3/4 is between 1/2 and 1, that −5 is further from 0 than −2.
  • Understanding the effects of operations — knowing that multiplying a positive number by a fraction less than 1 gives a smaller result.
  • Fluency with computation strategies — mental arithmetic, estimation, choosing between standard algorithm and informal methods.
  • Using benchmarks — knowing that 1/3 ≈ 0.33, π ≈ 3.14, √2 ≈ 1.41.

Teaching number sense at upper-primary level: Activities that build number sense include: (i) estimation tasks ('is the answer closer to 100 or 1000?'), (ii) open-ended problems ('find five different ways to make 3/4'), (iii) number talks (daily 5-minute discussions of mental computation strategies), (iv) comparing and ordering numbers across representations (fraction, decimal, percentage, number line).

NCERT's approach: Class 6 NCERT begins by reviewing natural numbers and whole numbers, then introduces integers through real-world contexts (temperature below zero, debts, depths below sea level). This contextualisation is critical for building intuitive understanding before formal rules.

Consecutive integers: If three consecutive integers are a, a+1, a+2, and taken in increasing order two at a time their products in some specific combination sum to a target — such problems require setting up an equation and solving, reinforcing the connection between number and algebra.

CTET Exam Focus

Number system questions in CTET Paper 2 Mathematics appear almost every cycle. The following patterns cover the vast majority of what is tested.

Pattern 1 — HCF/LCM from ratios. Given ratio m : n and LCM, find HCF using HCF × LCM = product of numbers. Numbers are mk and nk where k = HCF; LCM = mnk. Solve for k. Example: ratio 3:7, LCM 630 → 21k = 630 → k = 30 (HCF); sum HCF + LCM = 660.

Pattern 2 — Perfect squares / BODMAS chain. A multi-operation expression is given and candidates must evaluate using BODMAS correctly. Trap: forgetting that division and multiplication have equal precedence and must be done left to right. Also common: finding x = least number added to n to make perfect square, then computing a linear expression in x.

Pattern 3 — Counting multiples. 'How many numbers between 1 and N are divisible by each of a, b, c?' Answer: count multiples of LCM(a, b, c) in range. LCM(3,5,7) = 105; multiples of 105 up to 500 are 105, 210, 315, 420 — answer is 4.

Pattern 4 — Ratio → sum of cubes. Numbers in ratio a:b:c written as ak, bk, ck. Sum of cubes = (a³+b³+c³)k³ = given value. Solve for k; find sum = (a+b+c)k. Example: ratio 2:3:4, sum of cubes 33957 → 99k³ = 33957 → k = 7; sum = 63.

Pattern 5 — Properties of number sets. 'Which of the following is true about rational numbers?' Tests knowledge of closure, commutativity, the density property, and the difference between rational and irrational numbers.

Common traps: (i) Confusing HCF with LCM in word problems — read carefully whether the question asks for 'most' or 'least'. (ii) Forgetting that the sum of HCF and LCM is asked, not just one of them. (iii) In BODMAS, treating subtraction as having higher priority than addition.

Practice Questions

Q1. The value of 52 × 3 + 4 + √441 + 7 × 3 + 5 − 32 + 8 × 12 is:

  • 0
  • 5
  • 15
  • 21

Explanation: BODMAS: evaluate √441 = 21 first, then each multiplication (52×3=156, 7×3=21, 8×12=96), then add and subtract left-to-right: 156+4+21+21+5−32+96 = 271.

Source: CTET Jul 2024 Paper 2, Q34

Q2. If x is the least number which must be added to 955 to make it a perfect square, then value of 3x + 2 is equal to:

  • 20
  • 14
  • 11
  • 5

Explanation: 31² = 961. So 961 − 955 = 6 must be added; x = 6. Then 3x + 2 = 3(6) + 2 = 20.

Source: CTET Jul 2024 Paper 2, Q48

Q3. How many natural numbers between 1 and 500 are divisible by each of the numbers 3, 5 and 7?

  • 3
  • 4
  • 5
  • 6

Explanation: A number divisible by 3, 5 and 7 must be divisible by LCM(3,5,7) = 105. Multiples of 105 between 1 and 500: 105, 210, 315, 420 — exactly 4 numbers.

Source: CTET Jul 2024 Paper 2, Q49

Q4. The ratio of two numbers is 3 : 7 and their LCM is 630. Then, sum of the LCM and HCF of these numbers is:

  • 30
  • 300
  • 600
  • 660

Explanation: Numbers in ratio 3:7 are 3k and 7k. LCM = 21k = 630, so k = 30 = HCF. Sum of LCM and HCF = 630 + 30 = 660.

Source: CTET Jul 2024 Paper 2, Q60

Q5. Three numbers are in the ratio 2 : 3 : 4 and the sum of their cubes is 33957. What is the sum of the three numbers?

  • 54
  • 63
  • 72
  • 81

Explanation: Numbers 2k, 3k, 4k. Sum of cubes: (8+27+64)k³ = 99k³ = 33957, so k³ = 343, k = 7. Sum = (2+3+4)×7 = 63.

Source: CTET Jan 2024 Paper 2, Q35