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Q1. Consider the two statements about Queen Ratnamanjuri's lockers.
Statement I: For every factor d of a number n, the partner n/d is also a factor.
Statement II: A number has an odd number of factors only when some factor pairs with itself, i.e., when n is a perfect square.
Which of the following is correct?
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Q2. Which of the following numbers will have 1 as the units digit of its square?
I. 161
II. 249
III. 358
IV. 471
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Q3. A student writes that the number 4000 is a perfect square because 4 is a perfect square. Using rule about trailing zeros in squares, the student's claim is
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Q4. Using the prime factorisation method which of the following is NOT a perfect square?
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Q5. Find the smallest natural number by which 9408 must be multiplied so that the product is a perfect square. (Hint: 9408 = 2⁶ × 3 × 7²)
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Q6. Without computing exactly, the square root of 1936 lies between which two consecutive natural numbers?
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Q7. A square handkerchief has area 125 sq cm. What is the largest whole number length, in centimetres, that its side cannot exceed?
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Q8. Which of the following statements about trailing zeros of perfect cubes is correct?
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Q9. Extends cubes to negative integers. The value of (−6)³ is
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Q10. Using prime factorisation in triplets find the cube root of 3375.
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Q11. Find the smallest natural number by which 1323 must be multiplied so that the product is a perfect cube. (Hint: 1323 = 3³ × 7²)
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Q12. A pattern: 1 = 1³; 3 + 5 = 8 = 2³; 7 + 9 + 11 = 27 = 3³; 13 + 15 + 17 + 19 = 64 = 4³. The first odd number used to express 6³ as a sum of consecutive odd numbers is
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Q13. Which of the following is NOT a perfect cube?
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Q14. A Class 8 student in Rampur writes 12² = 24 in his notebook. The teacher's best diagnosis of the student's error is that the student is
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Q15. A Class 8 teacher wants her students to discover that 1 + 3 + 5 + … + (2n − 1) = n² without telling them the formula. The pedagogically richest classroom task for this discovery is